# Angle between hour and minute hands of analogue clock using C

By embeddedSoft
Published in Embedded C/C++
September 22, 2022 01
Calculation theory
02
Code
03
Code walk-through

This is a very interesting clock angle problem where the C program described in this article calculates the angle between the hour-hand and the minute-hand of an analog clock. In this example program if the user enters the hour and minute, then it should output the angle between the hour-hand and the minute-hand.

Example:

Input: hour = 10 and minute = 10

Output: 115 degree

The hour hand of a 12-hour analog clock turns 3600 in (12 x 60) minutes; in other words 0.50 per minute. Similarly, the minute hand would take 60 minutes to turn a complete 3600 (which is 60 per minute). The angle between the hour hand and minute hand is obtained by the difference between these angles.

## Code

```#include <stdio.h>
#include <stdlib.h>

int main()
{
unsigned int hour;
unsigned int minute;
unsigned int hAngle;
unsigned int mAngle;
unsigned int angle;

printf("Enter hour (12h format): ");
scanf("%u", &hour);

printf("Enter minute: ");
scanf("%u", &minute);

if (hour > 12u || minute > 60u)
{
printf("Invalid input!\n");
}
else
{
if (hour == 12u)
{
hour = 0;
}

if (minute == 60u)
{
minute = 0;
hour += 1u;
}

hAngle = 0.5f * ((hour * 60u) + minute);  // Hour hand angle with respect to 12:00
mAngle = 6u * minute;  // Minute hand angle with respect to 12:00

angle = abs(hAngle - mAngle);

if (angle > (360u - angle))
{
angle = 360u - angle;  // Getting the smaller angle value
}

printf("Angle between hour hand and minute hand is %d\n", angle);
}

return 0;
}
```

## Code walk-through

The code is simple and self explanatory. Angle between the hour hand and the minute hand is calculated at the below lines,

```        hAngle = 0.5f * ((hour * 60u) + minute);  // Hour hand angle with respect to 12:00
mAngle = 6u * minute;  // Minute hand angle with respect to 12:00
```

abs() library function is used to get the absolute value of the angle difference in angle = abs(hAngle - mAngle);

The below code section selects the smaller angle value from the two possible angle values,

```        if (angle > (360u - angle))
{
angle = 360u - angle;  // Getting the smaller angle value
}
```

## Tags

#c#embedded#clock-angle-problem
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